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April 19, 2018 ( Post 1 )

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Physics SOLUTIONS

Physics OBJ
1. DABBDCABDB
11 ACCCDDBDDD
21 DBAACADCBB
31 CCBBCCBDBD
41 BDCDCADBDC

PHYSIC ANSWER

(1a)
Strain can be defined as the ratio of extension per unit length
Strain=extension/length

(1b)
Strain=extension/length
Let original length=L
Final length=2L
Extension=2L-L=L
Strain=L/L=1

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4a)
Satellite are used for monitoring weather conditions

4b)
i)Rockets are used for space travel
ii)military uses,
iii)launching satellites into space

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5a)
i)They are used In making electric motors
ii)They are used In making radio loud speaker
iii)They are used In making aerial transistors
iv)They are used In making DC dynamo

5b)
Range = u²Sin2tita/g
At maximum range 
Sin2tita = 1
2tita =sin^-1(1)
2tita = 90dgrees 
Tita = 90/2 = 45degree

Maximum height reached = u²sin²tita/2g
=u²(sin45)²/2g
=200²(sin45)²/2(10)
=40000(1/√2)2/20
=40000(1/2)/20
=20000/20
=1000metres.

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(6)
Given constant = 2.9×10^-3mk
Temperature = 57degreeC = (57+273)k = 330k
Using landamaxT = constant 
landamaxT330 = 2.9×10^-3
landamax = 2.9×10^-3/330
landamax = 8.788×10^-6m
The speed of electromagnetic wave, v = 3×10^8m/s
Using V = f landa
f = v/landa
=3×10^8/8.788×10^-6
=3.4×10^13Hz

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7a) LASER stands for light amplification by stimulated Emission of Radiation

b). A laser is a device that emits a beam of coherent light through an optical amplification process

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10a) Diffraction refers to various phenomena that occur when a wave encounters an obstacle or a slit. It is defined as the bending of light around the corners of an obstacle or aperture into the region of geometrical shadow of the obstacle.

10bi
the angle of incidence beyond which rays of light passing through a denser medium to the surface of a less dense medium are no longer refracted but totally reflected.
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(12a) This is defined as the amount of energy that must be supplied to a nucleus to completely separate it's nuclear particles (nucleons)

(12b)
(i) They have short wavelength and high frequency.
(ii) They are highly penetrating.
(iii) They travel in straight lines.
(iv) They don't require material medium for their propagation.

(12c)
-It is used in production of electricity.
-It is used to study and detect charges in genetic engineering.
-It is used in agriculture.
-It is used in treatment of cancer.

(12di)
E = hf-hfo
but f = v/landa
E= v/landa.h - wo
Where wo = hfo = work function
f= frequency
landa = wavelength
Hence
hf = hfo - E
f = hfo - E/h
f = wo - E/h
Recall; that v = f landa
Therefore f = v/landa = 3×10^8/4.5×10-7
=3/4.5 × 10^8+7
=6.6×10^14Hz
f = 6.6×10^14Hz

(12dii)
E = hf
=6.6×10^-34 × 6.6×10^14Hz
=43.56×10^-20J

(12diii)
Energy of the photoelectron E = hf - vo
=Energy of incident electron - work function
=4.356×10^-19J - 3.0×10^-19J
=1.356×10^-19J
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